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1924 Iowa gubernatorial election

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1924 Iowa gubernatorial election

← 1922 November 4, 1924 1926 →
 
Nominee John Hammill James C. Murtagh
Party Republican Democratic
Popular vote 604,624 226,850
Percentage 72.72% 27.28%

County results
Hammill:      50–60%      60–70%      70–80%      80–90%      >90%
Murtagh:      50–60%

Governor before election

Nathan E. Kendall
Republican

Elected Governor

John Hammill
Republican

The 1924 Iowa gubernatorial election was held on November 4, 1924. Republican nominee John Hammill defeated Democratic nominee James C. Murtagh with 72.72% of the vote.

Primary elections

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Primary elections were held on June 2, 1924.[1]

Republican primary

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Candidates

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Results

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Republican primary results[1]
Party Candidate Votes %
Republican John Hammill 95,313 27.23
Republican W. J. Burbank 88,304 25.22
Republican J. H. Anderson 74,828 21.37
Republican Glenn C. Haynes 65,088 18.59
Republican Jonas D. Buser 15,459 4.42
Republican A. J. Banks 11,097 3.17
Total votes 350,089 100.00

General election

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Candidates

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  • John Hammill, Republican
  • James C. Murtagh, Democratic

Results

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1924 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Republican John Hammill 604,624 72.72%
Democratic James C. Murtagh 226,850 27.28%
Majority 377,774
Turnout
Republican hold Swing

References

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  1. ^ a b Guide to U.S. elections - CQ Press, Congressional Quarterly, inc. CQ Press. 2005. ISBN 9781568029818. Retrieved June 16, 2020.
  2. ^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved June 16, 2020.